Difference between revisions of "Length of a curve"

From apimba
Jump to navigation Jump to search
Line 12: Line 12:
  
 
<font size = "+2"><span>&#8747;</span></font>sqr(1+(30e<sup>−0.3t</sup>)<sup>2</sup>)dt
 
<font size = "+2"><span>&#8747;</span></font>sqr(1+(30e<sup>−0.3t</sup>)<sup>2</sup>)dt
 +
 +
entering this equation into the integral calculator [https://www.integral-calculator.com/ here] gives 77.8 degrees, which is about the same value calculated in the previous example using integration of the rate of change!

Revision as of 18:07, 1 April 2021

The length of a curve from point a to point b can be found using an integral of the first derivative of the equation:

equation = f(x)

first derivative = f '(x)

length = sqr(1+f '(x)2)dx

For the previous example of heating a liquid, the first derivative of the equation was f '(t)=30e−0.3t

so the length of the curve from 0 to 5 minutes would be:

sqr(1+(30e−0.3t)2)dt

entering this equation into the integral calculator here gives 77.8 degrees, which is about the same value calculated in the previous example using integration of the rate of change!